BuilderBoi

There are ${6 \choose 3 }= 20$ ways to choose 3 boys for the team

There is ${8 \choose 4} = 70$ ways to choose 4 girls for the team

Thus, there are $20 \times 70 = \color{brown}\boxed{1400}$ ways to choose 3 boys and 4 girls for the team. 

This is evidently from a test. A test is made to test YOUR capabilities, not ours. You should not be asking these questions, and we should not be answering these questions.

Parity Rules:

pos x pos = pos

pos x neg = neg

neg x pos = neg

neg x neg = pos

Both $1\over2$ and $12$ are positive, so the product must be $\color{brown}\boxed{\text {positive}}$

We know that $\angle BCE =30$. We know that $BC$ and $CE$ are the same length, so$\triangle{CEB}$ is isosceles. This means that $\angle CBE=\color{brown}\boxed{75^{\circ}}$

Part A: ${1\over2}\times{12}=\color{brown}\boxed{6}$

Part B: $\color{brown}\boxed{\text{positive}}$

763 thousanths is equal to 0.763, or $\color{brown}\boxed{7.63 \times {10^{-1}}}$

The smallest odd integer is $301$, and the largest one is $599$. There are $150$numbers in this series, so the sum is $150 \times 450 = \color{brown}\boxed{67,500}$

The max height occurs at $-b/2a$. This means that the x-axis of hte peak is ${-60\over-32} = 1 {7\over8}$

Subsitute $1 {7\over8}$ for $t$, and you find that the max height is $\color{brown}\boxed{77.25}$

The smallest number possible is 1, and the largest is 15.

Of these, all $\color{brown}\boxed{15}$ numbers are possible.

Look, we answer questions on this forum. We don't look up answer keys for you.