A ball travels on a parabolic path in which the height (in feet) is given by the expression −16t^2+60t+21, where t is the time after launch. What is the maximum height of the ball?
+2668 The max height occurs at −b/2a. This means that the x-axis of hte peak is −60−32=178
Subsitute 178 for t, and you find that the max height is 77.25
