A ball travels on a parabolic path in which the height (in feet) is given by the expression −16t^2+60t+21, where t is the time after launch. What is the maximum height of the ball?
+2668 The max height occurs at \(-b/2a\). This means that the x-axis of hte peak is \({-60\over-32} = 1 {7\over8}\)
Subsitute \(1 {7\over8}\) for \(t\), and you find that the max height is \(\color{brown}\boxed{77.25}\)
