In the figure shown, ABCD is a square and CDE is equilateral. What is the degree measure of CBE?
+36 We know that since the angle of a square is 90 degrees, and an equilateral triangle has an angle of 60. So, we know that BEC = 90-60 = 30.
CE = CD (because it is an equilateral triangle)
CD = CB (because it is a square)
CE = CB
Thus, CBE = CEB
Since a triangle's angles add up to 180, we know:
CBE + CEB + 30 = 180
CBE + CEB = 150
Since CBE and CEB are equal, they both equal 150/2 = 75
This means that Angle CBE = 75 degrees.
Let me know if I did anything wrong!
+2668 We know that \(\angle BCE =30\). We know that \(BC\) and \(CE\) are the same length, so\(\triangle{CEB}\) is isosceles. This means that \(\angle CBE=\color{brown}\boxed{75^{\circ}}\)
