BuilderBoi

The two points are 3 units across from each other.

For the 2 points to be exactly 5 units apart from each other, we need a 3 - 4 - 5 right triangle, because one of the legs is a 3, and the hypotenuse is a 5. 

The only points that meet these conditions are \((2,7) \) and \((2, -1)\).

Thus, \(n\) can equal \(-1\) or \(7\), and the answer is \(-1 \times 7 = \)___.

\(\sqrt {160} = \sqrt{16} \times \sqrt{10} = {4 \sqrt10}\)

\(\sqrt{252} = \sqrt{36} \times \sqrt7 = 6\sqrt7\)

\(\sqrt{245} =\sqrt{49} \times \sqrt5 = 7\sqrt5\)

\(\sqrt{75} = \sqrt{25} \times \sqrt{3} = 5\sqrt3\)

\({4\sqrt{10} \over 6\sqrt7} \times {7\sqrt5 \over 5\sqrt3} = {28\sqrt{50} \over 30\sqrt{21}}\)

\({28\sqrt{50}\over30\sqrt{21}} = {14\sqrt{50} \over 15\sqrt{21}} = {14 \times \sqrt{25} \times \sqrt2 \over 15\sqrt{21}} = {14 \times 5 \times \sqrt2 \over 15\sqrt{21}} = {70\sqrt2 \over 15\sqrt{21}}={14\sqrt2 \over 3\sqrt{21}}\)

\({14\sqrt2 \over 3\sqrt{21}} \times {3\sqrt{21}\over3\sqrt{21}} = {42\sqrt{42}\over 189} = \color{brown}\boxed{2\sqrt{42}\over 9}\)

Solving, \(x = -1\) and \(y = 2\). 

Thus, \(-1 - 2 = \color{brown}\boxed{-3}\)

ye its science... haven't heard of it?

We aren't here to do your work for you. 

This is standard form: \(ax^2 + bx + c = 0 \) In the quadratic formula: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) and \(b^2-4ac\) is the discriminant. If it is positive, there are 2 real solutions. If it is 0, there is 1 real solution. If it is negative, there are 2 imaginary solutions. 

gallons of what?

The only faces with 2 red faces are the edge pieces. There are \(\color{brown}\boxed{12}\) of them, just like Guest found. 

Ah... I forgot that you roll ONLY 1 dice. Sorry... 🤦

You forgot 2 and 2 EP, thus, there are 13 working cases out of 15 total cases.