An ordinary 6-sided die has a number on each face from 1 to 6 (each number appears on one face). How many ways can I paint two faces of a die blue, so that the product of the numbers on the painted faces isn't equal to \(4\)?

Guest Mar 14, 2022

#1**+2 **

you cannot paint the 1 and the 4 as the two faces

there are 6 c 2 ways to paint two faces = 15 ways

and ONE way (1 and 4) that you cannot paint = 14 ways

ElectricPavlov Mar 14, 2022

#2**+1 **

You forgot 2 and 2 EP, thus, there are 13 working cases out of 15 total cases.

BuilderBoi Mar 14, 2022