no one cares that ou cant solve it
1)
Applying the quadratic forumla gives us (x-3)(x^2+5x-2)
2)
(x-3)(x^2+5x-2)
done
you are being very disrespectful
3)
g(x) = 0 when x = 3, (-sqrt(33)-5)/2, (sqrt(33)-5)/2
The answer is (-3, -129)
why even bother to post answers if you cant solve it in the fist place
When it is rationalised, it is (4sqrt(119))/7
The solutions are
$(\frac{\sqrt{93}}{3} + 5, -\frac{\sqrt{93}}{3} + 5)$ $(-\frac{\sqrt{93}}{3} + 5, \frac{\sqrt{93}}{3} + 5)$
Let 3x + y + xy = 115, x > 0, y > 0 Solving this gives us y = (115 -3x) / (1 + x) So the point is (1, 56) x = 1, y = 56
3 + 56 + 56 = 115
So the answer is x + y = 1 + 56 = 57
+69 