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If x and y are positive integers for which 3x + y + xy = 115, then what is x + y?

 Nov 19, 2021
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Let 3x + y + xy = 115, x > 0, y > 0
Solving this gives us y  =  (115 -3x) / (1 + x)
So the point is (1, 56)
x = 1, y = 56

3 + 56 + 56 = 115

So the answer is x + y = 1 + 56 = 57

 Nov 19, 2021

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