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Let P and Q be constants. The graphs of the lines x + 5y = 23 and 16x + Py = Q are perpendicular and intersect at the point (8,3). Enter the ordered pair (P,Q).

 Apr 14, 2022
 #1
avatar+115 
-4

Vin or Chris gnna have to help you 

😎😎😎

 Apr 14, 2022
 #2
avatar+69 
+1

why even bother to post answers if you cant solve it in the fist place

ch1ck3n  Apr 14, 2022
 #4
avatar+115 
-4

To tell Sigh nvm why do i got to explain it to a idk 10 year older 

Kakashi  Apr 14, 2022
 #5
avatar+115 
-4

Prob 8

Kakashi  Apr 14, 2022
 #6
avatar+69 
+1

you are being very disrespectful

ch1ck3n  Apr 14, 2022
 #7
avatar+115 
-4

Am not i was just trying to tell the i cant solve this and u come in talking about why even bother to post answers if you cant solve it in the fist place why could u not let me be

Kakashi  Apr 14, 2022
 #8
avatar+69 
+1

no one cares that ou cant solve it

ch1ck3n  Apr 14, 2022
 #9
avatar+115 
-4

u talking obout me being Rude look at u being RUDEEEEE

Kakashi  Apr 14, 2022
 #3
avatar+69 
+1

The answer is (-3, -129)

 Apr 14, 2022
 #15
avatar+69 
+1

actually its wrong

ch1ck3n  Apr 14, 2022
 #11
avatar+115 
-2

STPPPPPPPPPPPPPPP

 Apr 14, 2022
 #12
avatar+115 
-2

TAKING AWAY MY LIKES

Kakashi  Apr 14, 2022
 #13
avatar+115 
-2

PlsSSSSS

Kakashi  Apr 14, 2022
 #14
avatar+69 
0

wow...

ch1ck3n  Apr 14, 2022
 #16
avatar+115 
-2

????????

Kakashi  Apr 14, 2022
 #17
avatar+115 
-4

i left for 10 min and ws hoping u was going to be Goneeee😮‍💨😮‍💨😞😮‍💨

Kakashi  Apr 14, 2022
 #18
avatar
+1

Slope of first line = - 1/5    perpindicular is = 5

 

16x + py = q        slope =   -16/p = 5    p = - 16/5

 

16 x - 16/5 p = q       sub in the point (8,3) to find the value of Q = 118.4

 Apr 14, 2022
 #19
avatar+124598 
+1

We can write  the first line as

 

y  =  (-1/5)x + 23/5     Note that the slope  =  -1/5

 

If the second ine is perpendicular to this one, then it will have a slope of 5

 

So we have  that

 

16x + Py  = Q

Py = -16x + Q

y = (-16/P ) + Q/P

 

This  means  that    -16/P  = 5    so   P =  -16/5

 

And since   (8,3)  is on this line then

 

16 (8) + (-16/5)(3)  =Q

128 - 48/5  = Q

592/5  = Q

 

So   (P, Q)  = (-16/5, 592/5)

 

cool cool cool

 Apr 14, 2022
 #27
avatar+578 
+2

Ah I knew I was close

 

When I was doing it I got 519/5 somehow for the y

 

smileysmileysmiley

Vinculum  Apr 14, 2022
 #20
avatar+115 
-3

so r they wrong 

 Apr 14, 2022
 #22
avatar+2455 
0

you tell me... are the answers the same or different?

BuilderBoi  Apr 14, 2022
 #26
avatar+115 
-2

No it not

Kakashi  Apr 14, 2022
 #21
avatar+2455 
+1

Because the lines are perpendicular, the other line has a slope of \(5\).

 

This means that the equation is \(y = 5x + b\)

 

Plugging in the point (8, 3), we get: \(3= 40+b\), meaning \(b = -37\)

 

Now, we have to convert \(y = 5x - 37\) into standard form. 

 

Subtracting \(5x\) from both sides, we get \(-5x + y = -37\)

 

Multiplying the equation by \(-{16 \over 5}\) , we get: \(16x-3.2y=118.4\)

 

From here, we can find the pair to be \(\color{brown}\boxed{(-3.2, 118.4)}\)

 Apr 14, 2022
 #23
avatar+115 
-4

S chris is wrong

Kakashi  Apr 14, 2022
 #25
avatar+2455 
0

No, our answers are the same... I just did mine in decimal, and Chris did his in fraction form.

BuilderBoi  Apr 14, 2022
 #28
avatar+115 
-2

Ohhhhh  kk

Kakashi  Apr 14, 2022
 #29
avatar+115 
-2

Lol Im trying so hard to at ur level

Kakashi  Apr 14, 2022
 #30
avatar+2455 
+1

Keep trying!!! With hard work and determination, you will get there!!

BuilderBoi  Apr 14, 2022
 #24
avatar+115 
-5

So**

 Apr 14, 2022

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