1) Factor out (a )(3a )
See the multiples of -8 and have them add up to -10 when one of them is multiplied by 3.
You get \((a-4)(3a+2)\)
2) The multiples of -3 are 1, -3 and -1, 3 and after trying out we get \((15x^2+3)(2x-1)\)
3) We see that we can do a difference of squares. \((4+5\sqrt x)(4-5\sqrt x)\) .
4) This equals \(4(a^2-4a+4)-81=4a^2-16a+16-81=4a^2-16a-65\)
Factor \(4a^2-16a-65=(2a+5)(2a-13)\) .
You are very welcome!
:P
(also thanks PartialMathematician for pointing out a mistake!)