We have 10 total
We have a 5/10 = 1/2 probability of a red on the first draw
We hav a 4/9 probability of a red on the second draw
So 1/2 * 4/9 = 4 / 18 = 2 / 9
32 / 50 = .64 = 64%
KER-RECKT.....!!!!!
Look at x / (x - 2)
Note that if x = 2 we get
2 / ( 2 - 2) =
2 / 0
But division by 0 is undefined.....so 2 will not work.....so.....it is extraneous !!!
Probability = Favorable Outcomes / Total Outcomes = 3 /10
Note that we have 3 favrorable outcomes....and 10 total outcomes
So 10 - 3 = Unfavorable Outcomes = 7
Odds = Favorable Outcomes / Unfavorable Outcomes = 3 / 7
Yep.....!!!
Any 10 can finish in 1st place .... any of the remining 9 can finish second..... any of the remaining 8 can finish third....
So.....the Fundamental Counting Principle gives us
10 x 9 x 8 = 720
172 / 1230 = ????
8 possible entrees x 5 possible desserts = ????
What's the answer, NSS ???
Remember....we are dealing with odds here
Odds = Favorable Outcomes / Unfavorable Outcomes
We have 20 Favorable Outcomes [ choosing a green can ] and 30 Unfavorable Outcomes [ choosing a red can ] ....so....
Odds = 20 / 30 = 2 / 3
