(2t + 3, 3 - 3t) = ( x, y)
This implies that
2t + 3 = x subtract 3 from both sides
2t = x - 3 divide both sides by 2
t = (x - 3) / 2 (1)
And we also have that
y = 3 - 3t substituting (1) in for t, we get that
y =3 - 3 ( x - 3) / 2 simplify
y= 3 - (3/2)(x - 3)
y= 3 - (3/2) x + 9/2
y= 6/2 - (3/2)x + 9/2
y= -(3/2)x + 15/2
Thus...we have a line with a slope of -3/2 and a y intercept of 15/2
Note that when x = 7 y = -(3/2)(7) + 15/2 = -21/2 + 15/2 = -6/2 = -3
And we can verify the y intercept.....when x = 0 ...... 2t = -3 ⇒ t = -3/2
Plugging this into 3 - 3(-3/2) = 3 + 9/2 = 6/2 + 9/2 = 15/2
Here is a graph of the parameterized line and the linear equation : https://www.desmos.com/calculator/ruklcsfe62
Note that the graphs coincide