Let Sarah's age = A
Let Kim's age = 4A
Let Betty's age = 4A + 3
So
A + 4A + 4A + 3 = 75
9A + 3 = 75 subtract 3 from both sides
9A = 72 divide both sides by 9
A = 8 = Sarah's age
4(A) = 4(8) = 32 = Kim's age
4(A) + 3 = 32 + 3 = 35 = Betty's age
12cm/ s * 60 s = 720 cm = distance traveled by the wheel in one minute
Circumference of the wheel = 2pi (12) = 24 pi cm
Revs per minute = 720 / [24 pi ] = 30 / pi ≈ 9.54 revs/ minute
x = 4t - 4 y = -2t + 7
x + 4 = 4t y -7 = -2t
[ x + 4] / 4 = t [ 7 - y ] / 2 = t
This implies that
[ 7 - y ] / 2 = [ x + 4 ] / 4
4 [ 7 - y ] = 2 [ x + 4]
7 - y = (2/4) [ x + 4]
7 - y = (1/2) ( x + 4) multiply through by -1
y - 7 = (-1/2( ( x + 4)
y = (-1/2)x - 2 + 7
y =(-1/2) x + 5
Honolulu and Juneau are obvious
Carson City is surprising !!!
You could win a lot of "bar bets" with this question.....
The points (4,3) and (0,8) are on the graph
Slope = [ 8 - 3 ] / [ 0 - 4 ] = 5 / -4 = -5 / 4
Using either point we have that
y = (-5/4)x + 8
We can write
log y^5 (x^3) = log y (x^k)
Using the change of base theorem we can write
log x^3 log x^k
_______ = ________ simplify
log y^5 log y
3 log x k log x
______ = ________
5 log y log y
(3/5) log (x) / log (y) = (k) log (x) / log (y)
(3/5) = k
First one
Let the width of the box = 25.5 cm
Let the width of the disc = 1.6 cm
25.5 / 1.6 = 15.9375 means that we could not stack 16 discs in the box....we could only fit 15
HAHAHA!!!!.....most of the thanks should go to Heureka!!!!
Good!!!.....understanding is the most important part...!!!
Ah....I didn't notice the "to the nearest cm" thing
Let the inner dimensions be 14.5 x 27.5
And let the outside dimensions be as shown
The max for the blue area is (21) (42) - ( 14.5)(27.5) = 882 - 398.75 = 483.25 cm^2
