In the coordinate plane, we plot the point $(4t - 4, -2t + 7)$ for every real number $t$ to obtain a graph $\mathcal{G}.$ For example, when $t = 2$, we have $4t - 4 = 4$ and $-2t + 7 = 3$, so the point $(4,3)$ lies on the graph $\mathcal{G}$.
(b) Show that every point on the line $y = -\frac{x}{2} + 5$ lies on the graph $\mathcal{G}.$
Hints please
+130511 x = 4t - 4 y = -2t + 7
x + 4 = 4t y -7 = -2t
[ x + 4] / 4 = t [ 7 - y ] / 2 = t
This implies that
[ 7 - y ] / 2 = [ x + 4 ] / 4
4 [ 7 - y ] = 2 [ x + 4]
7 - y = (2/4) [ x + 4]
7 - y = (1/2) ( x + 4) multiply through by -1
y - 7 = (-1/2( ( x + 4)
y = (-1/2)x - 2 + 7
y =(-1/2) x + 5
