sin (A + B) = sin Acos B + sin B cos A
cos A = −√2/3
sin A = - √ ( 3^2 - (√2)^2 ) / 3 = - √ [9 - 2] / 3 = - √7 / 3
tan B = 4/3
cos B = 3 / sqrt (3^2 + 4^2) = 3 / sqrt 25 = 3/5
sin B = 4/sqrt (3^2 + 4^2) = 4 /sqrt 25 = 4/5
So we have
sin (A + B) = ( -√7 / 3) (3/5) + (4/5) (-√2 / 3) =
-3√7 - 4√2 - [ 3√7 + 4√2 ]
___________ = ______________
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