5 builders take 3.5 hrs to build a wall
So...to calculate the hours, H, that it will take 2 builders to build the same wall we have
5 * 3.5 = 2 * H
17.5 = 2 * H divide both sides by 2
8.75 = H
So the total amt to be paid =
2 workers at 9.30 pounds/hr * (8.75) hrs = 162.75 pounds
Ounces needed = (6/2) * 5 = 3 * 5 = 15
Grams needed = 15 * 28 = 420
She has 240 grams
So...she needs 420 - 240 = 180 more grams
I'm assuming that you mean "adjacent vertices"
If so.....the square of the distance between these points is the area of the square...so...
Area = (2-3)^2 + (4 -1)^2 = 1 + 3^2 = 10 units^2
Here's one way to do this
arctan (13/9) + arctan (1/3)
______________________ = theta
2
tan (theta) =
tan [ ( arctan (13/9) + arctan (1/3)) / 2 ] = 3/4 = the slope of the bisector
See the graph here : https://www.desmos.com/calculator/jssgzsmyoq
r = √ [ (-5√3)^2 + 5^2 ] = √ [75 + 25 ] = √100 = 10
θ = arctan ( 5 / [ -5√3] = -1 /√3 = -pi/6
But this point is in the second quadrant so theta = 5pi/6
-5√3 + 5i = 10 [cos (5pi/6) + i sin ( 5pi/6) ]
Very nice, LuckyDucky!!!!
a) Green = 300 (1/5) = 60 times
b ) P(purple) = 72 / 300 = 6/25
c) If spun 1000 times, Blue would come up
1000 (45) / (300) = (10/3) 45 = 150 times
Outcome Void Fail Success
Freq 96 60 244
Rel Feq .24 .15 .61
b) 1000 *.24 = 240 times
Factors of 30 = 2,3,5,6,10,15,30
Relatively prime to 30
83, 79, 77, 73, 71, 67, 61, 59, 53, 49, 47, 43, 41, 37, 31, 29, 23, 19, 17, 13, 11, 7
AB = sqrt [ (-6 - 9)^2 + (6 - 6)^2) ] = sqrt [ 15^2] = 15
BC = sqrt [ ((9- 9)^2 + ( -2 - 6)^2 ] = sqrt [ 64] = 8
AC = sqrt [ (-6 - 9)^2 + (-2 - 6)^2) ] = sqrt [ 15^2 +8^2] = sqrt [ 289] = 17
Perimeter = 15 + 8 + 17 = 40
