We can write
y = a ( x - 2) ( x - 4) and we know that ( 3, 6) is on the graph so
6 = a ( 3 - 2) ( 3 - 4)
6 = -1 a
a = -6
So we have
y = -6 ( x - 2) ( x - 4)
y = -6 ( x^2 - 6x + 8)
y = -6x^2 + 36x - 48
See the graph here : https://www.desmos.com/calculator/puneh6dg7u
Note that arc SV = 180° and arc SW = 72°
So
arc SV - arc SW = arc WV
180 - 72 = arc WV = 108°
Discovering a pattern is always a useful thing to try in these problems
Note
55 * 11 = 605
55 * 111 = 6105
55 * 1111 = 61105
55 * 11111 = 611105
It appears that the sum = 6 + 5 + ( n - 2) * 1 where "n" is the number of 1s we are multiplying by
So...multiplying by 55 " 1s " gives the sum : 6 + 5 + (55 - 2) ^ 1 = 11 + 53 = 64
I "unblocked" them, EP....are they showing up now ???
The bases are parallel
Consecutive angles formed by a transversal cutting parallel lines are supplementary . ...so...
"a" is supplemental to 61° = 180 - 61 = 119°
"b" is supplemental to 132° = 180 - 132 = 48°
The line falls from left to right.....so we have a negative slope.....this eliminates answers A and B
The y intercept = (0, 6)
The x intercept is ( 12 0)
Slope = ( 6 - 0 ) / ( 0 - 12) = 6 / - 12 = - 1/ 2
D is correct
arc QT =180°
arc TU = 47°
arc QTU = arc QT + arc TU = 180 + 47 = 227°
Equation of line
y =(-1/2) (x - - 2) + 2
y = (-1/2) (x + 2) + 2
y = (-1/2)x - 1 + 2
y = (-1/2) x + 1
(-2,2) on the line
(0, 2) not on line
( 4, -1) on line
(0,1) on line
(-3, 8) not on line
We can form a right triangle wirh legs of 4 and (7 - 2) = 5
Then
x = sqrt [ 4^2 + 5^2 ] = sqrt [ 16 + 25 ] = sqrt [ 41 ] = 6.4
We have the points ( - 1, 5) abd ( 0 , -5)
Slope = ( -5 - 5) / ( 0 - - 1) = -10 / 1 = - 10
Using the slope and ( 0. -5) we have
y = -10 ( x - 0) - 5
y = -10x - 5