write a linear function that satisfies the given conditions. h(-1) = 5 and h(0) = -5
Ok here:
Slope:
-1/10
y = -1/10 x + a
-1 = -1/2 + a
a = 1/2 - 1 = -1/2
y = -(1/20)x - (1/2)
We have the points ( - 1, 5) abd ( 0 , -5)
Slope = ( -5 - 5) / ( 0 - - 1) = -10 / 1 = - 10
Using the slope and ( 0. -5) we have
y = -10 ( x - 0) - 5
y = -10x - 5
@CPhill. Oops, I calculated the slope wrong.
+312 
