3). A. Given that TAN(A)==1.7124, find angle A
We can use the tangent inverse to find this
tan-1 (1.7124) = about 59.7 degrees......this could also be a 3rd quadrant angle = (180 + 59.7) = about 239.7 degrees
B. Given that SIN(A)=0.7734, find angle A
Again ..... we can use the sine inverse to find this
sin-1(.7734) = about 50.66 degrees.......this could also be a 2nd quadrant agle = (180 - 50.66) = about 129.34 degrees
