Let our 4 numbers be a1,a2,a3,a4. Since we know that a1=a4, we replace it, getting us:
a1,a2,a3,a1
Therefore, we know that the last three numbers form an arithmetic sequence. We can represent each of the other terms in terms of a2. We know that the common difference is 6, therefore, we can write our 4 numbers as:
a1,a2,a2+6,a2+12
Since the first number is the same as the last number, we can also replace the first number with the last number, which gets us:
a2+12,a2,a2+6,a2+12
Let r be the common ratio between our numbers. Then, we know that:
r(a2+12)=a2,ra2=a2+6,
Solving this systems of equations by subsitution, we find out that a2=−4,r=−12. Therefore, our 4 numbers are:
8,−4,2,8
.