quadratic

We first combine like terms and get:

\(x^2 + 2x + 9\)

Then, we complete the square to get:

\(x^2 + 2x + 1 + 8\)

\((x+1)^2 + 8\)

Therefore, the minimum value of x is equal to -1

Oops sorry I replaced x with t

t^2 +2t +9       will have a minumum value at    t = - b/2a    =  - 2/2 = -1