Divineology

We start with $2,000. He then uses \(\frac14 + \frac18 = \frac38\) of his salary. This means he has \(1 - \frac38 = \frac58\) of his salary left.

\($2000 \cdot \frac58 = $1,250\)

Thus, he has $1,250 left.

This problem is fairly simple, you just need to assign values to \(x\) and \(y\), then solve the equation.
 

Using the equation \(4x=3y\), we can assign \(x=3\) and \(y = 4.\)

\(\frac{2x+y}{3x+4y} \)

\(\frac{2(3)+4}{3(3)+4(4)}\)

\(\frac{6+4}{9+16}\)

\(\frac{10}{25}\)

\(\boxed{\frac{2}{5}}\)

\(11*101+110 = 1221\)

That is incorrect.

The probability will always be % \(50\) because each turn, there is a 50-50 chance that the coin will be heads or tails.

It didn't have any guts. Ha, ha.

Ok, I just wanted to make sure! 

Did you mean to add a slash here? 1/((1 - a)(1 - ab)) + 1/2*a/((1 - a)(1 - ab)) + 1/2*b\(/\)((1 - a)(1 - ab)) = (a + b + 2)/(2(1 - a)(1 - ab))

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