Find the unique pair of real numbers (x,y) satisfying (3x2−12x+16)(2y2+6y+9)=18.
Using the quadratic formula, we get (x,y) = (4,-3).
Here's what Wolframalpha finds
https://www.wolframalpha.com/input/?i=%283x%5E2-12x+%2B+16%29+%282y%5E2+%2B+6y%2B+9%29++%3D+18
+87 
