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Find the unique pair of real numbers \((x,y)\) satisfying \((3x^2 - 12x + 16)(2y^2 + 6y + 9) = 18\).
 

 Nov 20, 2020
 #1
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Using the quadratic formula, we get (x,y) = (4,-3).

 Nov 20, 2020
 #2
avatar+120158 
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Here's what Wolframalpha finds  

 

https://www.wolframalpha.com/input/?i=%283x%5E2-12x+%2B+16%29+%282y%5E2+%2B+6y%2B+9%29++%3D+18

 

cool cool cool

 Nov 20, 2020

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