Find the unique pair of real numbers \((x,y)\) satisfying \((3x^2 - 12x + 16)(2y^2 + 6y + 9) = 18\).
Using the quadratic formula, we get (x,y) = (4,-3).
Here's what Wolframalpha finds
https://www.wolframalpha.com/input/?i=%283x%5E2-12x+%2B+16%29+%282y%5E2+%2B+6y%2B+9%29++%3D+18
+87 
