algebra

This problem is fairly simple, you just need to assign values to $x$ and $y$, then solve the equation.
 

Using the equation $4x=3y$, we can assign $x=3$ and $y = 4.$

$\frac{2x+y}{3x+4y}$

$\frac{2(3)+4}{3(3)+4(4)}$

$\frac{6+4}{9+16}$

$\frac{10}{25}$

$\boxed{\frac{2}{5}}$