algebra

This problem is fairly simple, you just need to assign values to \(x\) and \(y\), then solve the equation.
 

Using the equation \(4x=3y\), we can assign \(x=3\) and \(y = 4.\)

\(\frac{2x+y}{3x+4y} \)

\(\frac{2(3)+4}{3(3)+4(4)}\)

\(\frac{6+4}{9+16}\)

\(\frac{10}{25}\)

\(\boxed{\frac{2}{5}}\)