Dragan

arc XY = 170         arc VW = 110

arc VX + arc WY = 360 - ( 170+110 ) = 80

angle U = ( arc WY - arc VX ) /2 

30 = ( 70 - 10 ) / 2 

arc WY = 70º 

2x+2+5x+3=180

Hi, Noori! I'm gonna use the angle bisector theorem to solve this simple question. 

1/   AB = MR = 10                (AB and MR are diameters of a circle O)  AB ⊥ MR

2/   AP : PB = 8 : 6            AP = 8( 10 / 14 ) = 5.714285714

3/   PO = AP - AO = 0.714428714

4/   Triangle PMO is the right-angled triangle.

5/   Angle PMO = arctan(PO / OM) = 8.130102354º

6/   And finally,   CM = cos(PMO) * MR = 9.899494937   or  7√2   

x = 360 - ( 110 +110 + 65 )

Trapezoid HGFE is inscribed in a circle, with EF parallel GH. If arc GH is 70 degrees, arc EH is x^2 - 2x degrees and arc FG is 56 - 3x degrees, where x > 0, find arc EPF, in degrees.

arc EH = arc FG

x² - 2x = 56 - 3x         x = 7

7²- 14 = 35               56 - 21 = 35

arc EPF = 360 - 140 = 220º

Angle  x = 129 degrees 

∠CAB = ∠CBA = 90º-65º = 25º

∠y = 180º - 2*25º = 130º

∠x = 130º / 2 = 65º

∠z = 180º - 2*65º = 50º  

( 14x+7 - 7x+11 )/2 = 3x+4

(7x-4) /2 = 3x+4

x = 12

3x+4 = 3*12+4 = 40               angle WVT = 40º  

5 * 8 * 12 = 480cm³

480 / (8 * 15) = 4

The depth of milk is 4cm