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Trapezoid HGFE is inscribed in a circle, with EF parallel GH. If arc GH is 70 degrees, arc EH is x^2 - 2x degrees, and arc FG is 56 - 3x degrees, where x > 0, find arc EPF, in degrees.

 Aug 11, 2020
 #1
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Trapezoid HGFE is inscribed in a circle, with EF parallel GH. If arc GH is 70 degrees, arc EH is x^2 - 2x degrees and arc FG is 56 - 3x degrees, where x > 0, find arc EPF, in degrees.

 

arc EH = arc FG

 

x- 2x = 56 - 3x         x = 7

 

72- 14 = 35               56 - 21 = 35

 

arc EPF = 360 - 140 = 220º

 Aug 11, 2020
 #2
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Thanks!

qwertyzz  Aug 11, 2020

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