ElectricPavlov

Arrange line equation into form y = mx+b    m = slope        (parallel slope will be the same value)

2x+3y = 21

y = -2/3x +7       slope = -2/3

Now use your two points to calculate slope = - 2/3

(y1-y2) / (x1-x2) = slope = -2/3

(-9 - 17) / (2-j) = - 2/3          solve for 'j'

I made a mistake in my calculations....as guest found below... answer is 11 .       yikes.

Let x =   sqrt 11(sqrt11 (sqrt11......     your question

x² = 11 sqrt 11 sqrt 11......        this is   11x

so 

x² = 11x    divide by x

x = 11             Well ...that was easy!   D'Oh!   

Thanx, Guest !

From quadratic equation

x=1+22360700i

x=1−22360700i      Take it from here .....

or   just plugging into the quadratic formula

    you will get as roots      4 +- sqrt (big negative number)

                                                             4

       or       just    1 + big imaginary number     and     1 - big imaginary number

                 summed , the 'big imaginary number' s cancel out and you are left with   1 + 1 = 2

Just put in 77 for y ...then solve for 't ' using the Quadratic formula

77 = - 6t² + 43t   

-6t² +43t -77 = 0 

    a = -6     b = 43    c = -77

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)          throw out any negative 't' values

I hope you actually looked at the method of solution and understand !

You are welcome .....

The top is  equivalent to  482/99

the bottom is                  392/99

(482-392) / 99 = ...........            (it's    .909090909.......)

at   point   0,5

       5 = a(0²) + b (0)   + c

       5 = c

Now sub in the point  1,10

   10 = a(1^2) + b(1) + 5

   10  = a + b + 5

     5 = a + b

Now  put in the point 2,19

19 = a (2^2) + b(2) + 5

19 = 4a + 2b + 5

14 = 4a+ 2b

Now you have two (RED) equations and two unknowns (a and b)   solve for a and b

a+b = 5

4a+ 2b = 14        I'll solve by 'elimination'    

                              ....   multiply the first equation by -2   then add to the second equation to get :

2a = 4

a = 2               and since   a+b = 5    b = 3       and  c = 5

See your original post for further help.....

a+b =8

    b = 8-a

a+c = -5

    c = -5 - a

b+c = -3

 substitute  

   8-a   +  -5 -a  = -3

   3 - 2a = -3

      -2a = -6

         a  = 3           you  should be able to continue from here.......

Well, as you can see, the function is a line

y = mx + b    is  slope intercept form of a line   m = slope  b = y axis intercept (when x = 0)

Find two 'convenient' points like   -3,2    and   0,-4

    calculate the slope, m   as    (y1-y2) / (x1-x2)

       you will then have   y = mx + b

      then put one of the points into your building equation to calculate 'b'  

             (BTW you can 'see'  'b' where x = 0 the value of b is shown as -4 on the graph)