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The graph of y=ax^2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c.

 

I tried what EP said, and plugged in 0,5, where 5 is y, and 0 is x. I got c = 5.

 

Then I plugged in 1,10 y = 10, x = 1.

 

Plugged in 2,19 y = 19 x = 2.

 

Then i substituted and I got a wonky answer... 

 Jul 18, 2020
 #1
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See your original post for further help.....

 Jul 18, 2020

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