y = 1 (x)
find perpendicular line
y = -x
that passes through the point (5,7)
y = -x + 12
Intersection point is 6,6 ( found by equating y = x and y = -x +12 )
(6,6) IS THE midpoint BETWEEN the original point (5,7) and the reflected point (x,y)
so ( 5+x ) / 2 = 6 and (7+y) / 2 = 6 shows (x,y) to be (7, 5)
This is pretty easy to see with a line y = x .....but this is the method to use for more diffiicult line equatins such as ' y = 5x ' etc......