+0  
 
0
8
1
avatar+1679 

In the Olympic women's skating competition, the gold medal goes to first place, silver to second, and bronze to third. If there are 19 skaters, including 2 Americans and 5 Canadians, in how many ways can the medals be awarded to three of the 19 skaters so that an American wins a medal, and a Canadian wins a medal?

 Jan 15, 2024
 #1
avatar+36919 
+1

There are 2 Americans ...they can be either 1st 2nd 3rd =   6 ways 

   the 5 Canadians fill one of the two remaining spots = 10 ways                  10 x 6 = 60 ways for ONE cnadian and ONE American to medal together 

        the final spot is then for one of the remaining 12 

                12 x 60 = 720 ways 

 

If a Canadian or American can win the third spot , there are 17 skaters that can fill the third spot 

               17 x 60 = 1020 ways 

 

(I think) 

 Jan 15, 2024
edited by ElectricPavlov  Jan 15, 2024

3 Online Users

avatar