Max height will be at time, t = -a/(2b) = - 64/(2*-16) = 2 seconds
Substitue this time into the equation to find max height
-16(2^2) + 64(2)+31 = 95 ft max
$ 38. = 755.56 Mex peso at current excange rates is what I find.
Yes, as Chris said, but miscalc'd -b/2a = - -6/(2*-1) = -3
3 / (sqrt 2 - 1) ? Anyone else?
3 sqrt2 / (sqrt2-1) ?
8 ? Now I'm just guessing! I have no idea!
The number of TERMS in the ARITHMETIC series:
(2008 -3)/5 + 1 = 402
I count 5....but I'm not sure.
You will have a -5x^2 +42x^2 and a -x^2 = +36x^2 soooooo 36
Similar to previous posting
the number of books sold 123-3p
revenue = (123-3p) * p = -3p^2 + 123p max = -b/2a = -123/-6 = 20.5 dollars /book
[123-3(20.5)] * 20.5 = $ 1260.75 max revenue
If the number of books sold = 130-5p then revenue will be (130-5p)p = -5p^2+130p
the maximum can be found by graphing or by the fact that the max will be -b/2a = -130/-10 = 13 dollars/book
[130-5(13)] (13) = $845 max revenue.
Are you sure of your equation? Is it + 5 at the end....or should it be (x+5) multiplier?
