Three circles of radius \(s\) are drawn in the first quadrant of the \(xy\)-plane. The first circle is tangent to both axes, the second is tangent to the first circle and the \(x\)-axis, and the third is tangent to the first circle and the \(y\)-axis. A circle of radius \(r>s\) is tangent to both axes and to the second and third circles. What is \(r/s\)?
3 / (sqrt 2 - 1) ? Anyone else?
3 sqrt2 / (sqrt2-1) ?
8 ? Now I'm just guessing! I have no idea!
The answer is approximately 9 (maybe exactly 9)
But I have not worked out how to do it properly.
Sorry Alan, it has just been pointed out to me that it was your post.
Thanks for your clear explanation :)
Thanx, Alan..... I looked at that one for some time, but could not find an answer ! You made it look too easy.....