How many numbers are in the list $2008,2003,1998,…,8,3?$ ?
I think the answer is 401.2 but im not sure
I count 5....but I'm not sure.
The number of TERMS in the ARITHMETIC series:
(2008 -3)/5 + 1 = 402
Last term = First term - 5( N - 1) where N is the number of terms
3 = 2008 - 5(N - 1) subtract 2008 from both sides
-2005 = -5N + 5 subtract 5 from both sides
-2010 = - 5N divide both sides by - 5
402 = N
+37166 
