To plaigerize cphill's answer from earlier:
Since the y coordinate of the focus is -2 and the directrix is y = -1 .....the focus lies below the directrix ..
...so....this parabola opens downward
The vertex lies 1/2 of the way between the focus and directrix......to find this we have (0, [ -2 + - 1] /2 ) =
(0, -3/2 ) = (h, k)
"p' is the distance between the vertex and focus = l -3/2 - (-2) l = 1/2
So....we have the form
4(-p)[ y - k ] = (x - h)^2
the sign of 'p' tells us which way the parabola faces......we determined that this is a DOWNWARD facing parabola so - p goes in the equation
4(-1/2) [ y - - 3/2)] = (x - 0)^2
-2 (y+3/2)= x^2
y+3/2 = -1/2 x^2
y= -1/2 x^2 - 3/2
Maybe it would be clearer at THIS step:
"p' is the distance between the vertex and focus = l -3/2 - (-2) l = 1/2 " to say p = -1/2 becuase it is a downward opening parabola