ElectricPavlov

The hole in the graph occurs when the denominator = 0   (undefined point)

    this occurs at x = 3

The NUMERATOR factors in to  (x-3)(x+3)     this reduces to  (x+3) when you 'cancel out' with the denominator (x-3)

     this value at x = 3          is (x+3) = 6

so the point of the hole is    3,6

Wellllll...since it is between 1.8 and 1.9   let's pick   1.85  and substitute that into the equation and look at the result to see if it = 1

1.85      1.85^3 - 3(1.85) = .7816     Kinda close, lets try  1.86

1.86                                =  .8548   closer...try 1.87

1.87                                =  .9292   getting there ....try 1.88

1.88                                = 1.0046     BINGO !   

1.88   to 2 decimal places  is a solution to  x^3 - 3x = 1

Changing the denomintor from   x-3    to x+4      shifts LEFT by   7

changing the +1   to  +3    shifts UP   2 

5t+4 >19     subtract 4 from both sides of the equation

5t > 15         divide both sides by 5

t>3            Answer A

  Actually the equation SHOULD read 5t+4 >= 19   because if he rides EXACTLY 3 loops and to-from the park it would be exactly 19 miles

Divide both sides of the equation by 26.

Actual Mechanical Advantage is a more realistic number than IMA , as  AMA accounts for friction etc.

80N x 1m = 80 N*m    (torque)    the work 'in'

Output   150 N * .5 m = 75 N* m   the work 'out     (so some of your input is lost in the form of friction, sqeaks,slippage etc)

AMA =   output F / input F  =   150/80 =  1.875      ( I have not seen this subject in a long time......pretty sure of my answers though)

IMA = Ideal Mechanical Advantage  = force multiplier

280 N out is the input force multiplied by 7     so the input force is  280n/IMA = 280/7 = 40 N

3^m   *    3ⁿ    = 3^m+n

^sooooooo....

3^m+n  = xy

I'll give ya partial credit.....  1/2 of a heart.    Haha  

Not exactly sure what you are asking, but I will go with this:

8x=140   divide both sides of the equation by 8

x = 17.5 degrees

Maybe   8x + 140 = 180   ??    subtract 140 from both sides

              8x = 40                       divide both sodes by 8

                 x = 5