What are the coordinates of the hole in the graph of the function f(x) ?
f(x) = x^2 − 9 / x − 3
(I think its [3,6] because that's where it becomes 'undefined'. Am I wrong? Please let me know, I appreciate it).
+36916 The hole in the graph occurs when the denominator = 0 (undefined point)
this occurs at x = 3
The NUMERATOR factors in to (x-3)(x+3) this reduces to (x+3) when you 'cancel out' with the denominator (x-3)
this value at x = 3 is (x+3) = 6
so the point of the hole is 3,6
+36916 The hole in the graph occurs when the denominator = 0 (undefined point)
this occurs at x = 3
The NUMERATOR factors in to (x-3)(x+3) this reduces to (x+3) when you 'cancel out' with the denominator (x-3)
this value at x = 3 is (x+3) = 6
so the point of the hole is 3,6
