gb1falcon

Great! Thanks for figuring that out! I will use that answer for geometry. It is very well written and understandable.

Please try to include a question in a request. figur n does not signify anything to potential answerers.

It is an equilateral triangle, so PX is a median. Then we need to calculate the altitude of a 30-60-90 triangle from the 90-degree angle. Perhaps another user knows a formula for this?

\(xy + x = \frac{3x + 2y + z + y + 2z}{3}\)

\(3xy + 3x = 3x + 2y + z + y + 2z\)

\(3xy=2y+y+2z+z\)

\(3xy=3y+3z\)

\(xy=y+z\)

\(x=1+\frac{z}{y}\)

Assuming that y is not 0.

What he is looking for is an expression, so it is 4/(1/2).

This question cannot be answered correctly, since Grogg's dad's age has to be both a multiple of 4 (even) and seven (or one) more than a multiple of 6 (odd). Since it cannot be even or odd, there is no answer. If you typed incorrectly, the other answers may prove useful to you.

1. If the right angle is at ABC, then the base is 6 and the height is 8, so use the formula to get 6*8/2=48/2=24.

2. Since the angles of a triangle add to 180, BAC=180-135-30=180-165=15.

I'm not sure all of that is correct.

First, part B. If only 11 total students are in drama, and 9 of them are in band, then only 2 of them are in drama but not band.

Then, for part A, 19+11-9 students are in either drama or band, which is 21, so 80-21=59 students are in neither.

For part C, if 19/80 were in band, then change the ratio to 118.75/500 students in band.

I think that acyclics misread the question and gave answers to a different problem.

I am assuming from the points shown at the end that this is homework, so I will not give complete answers.

Do subtraction given the values to figure out the rest of the table. For example, the other one in the text message column is 69-22=47. Once you have figured out all of those, you should have the answer to Part A. It is in italics. For part B:

                                     Text Message            Have Not Sent a Text Message          Total

Have Taken a Selfie            22                                            38-22                                38

Have Not Taken a Selfie     47                                            90-38-47                         90-38

Total                                   69                                              90-69                               90

The bold ones are the ones you should add up and then take the percentage of those out of 90 (the total students).

That seems good! Here is a shorter way: 21-5=16 who play either sport. 

14+6=20 total sports. 20-16=4 players who play both sports. Therefore the probability is 4/21.