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Inside a square with side length , two congruent equilateral triangles are drawn such that they share one side and each has one vertex on a vertex of the square. What is the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles?

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 May 2, 2023
 #1
avatar+1348 
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Let O be the center of the square, and let E, F, G, and H be the points where the sides of the square intersect the sides of the triangles. Since the triangles are equilateral, OE=OF=OG=OH=5. Let s be the side length of the largest square that can be inscribed in the space inside the square and outside of the triangles. Since O is the center of the square, s must be less than 5.

Let x=OE−s. Since s is the side length of the inscribed square, OE+s=OE−x+2s=OE+x=5. Therefore, x=2.

Since OE=5, the side length of the inscribed square is s=OE−2=5−2=3​.

 May 2, 2023
 #2
avatar+214 
0

I'm sorry, I forgot to include the side length of the square. I must have missed typing it. The side length of the square is 10. Does that change your answer?

 May 2, 2023

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