geno3141

80 can be formed by 1x80, 2x40, 4x20, 5x16, and 8x10, so the factors are 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.

Call the 7 seats (from left to right) seats 1, 2, 3, 4, 5, 6, 7.

A can sit in any of seats 1 through 6 with B sitting to his right.  (Six different places.The other 5 persons have 5x4x3x2x1 different ways to arrange themselves for each of the six different places, for a total of 6x5x4x3x2x1 ways.)

Also, A can sit in any of seats 2 through 7 with B sitting to his left.  (Six different places. Like the above, the other 5 persons have 5x4x3x2x1 different ways to arrange themselves for a total of 6x5x4x3x2x1 ways.)

This gives a total of 2 x 6x5x4x3x2x1 ways.

The mean of the data is 180.4

The standard deviation of the data is 70.8

An outlier is defined to be a value that is at least 1.5 standard deviations either above or below the mean.

1.5 x 70.8  =  106.2

Subtracting 106.2 from the mean gives 180.4 - 106.2  =  73.8. Since there is no value smaller than 73.8, there is no outlier below the mean.

Adding 106.2 to the mean gives 180.4 + 106.2  =  286.2.  Since 325 is greater than 286.2, 325 is an outlier.

For each of these, find two points.

First, enter 0 for x, and solve for y

Then, enter 0 for y, and solve for x.

For instance:  8x + 4y  =  32

First:  let x = 0  --->   8(0) + 4y  =  32

                                  0 + 4y  =  32

                                        4y  =  32

                                          y  =  8     --->  Plot the point (0, 8)

Then:  let y = 0   --->   8x + 4(0)  =  32

                                    8x + 0  =  32

                                          8x  =  32

                                            x  =  4     --->  Plot the point (4, 0)

Then draw the line that passes through the points  (0, 8)  and  (4, 0).

In normalcdf(30, 70, 16, 0.1)  the 30 represents the lower limit, the 70 represents the upper limit, the 16 represents the mean, and the 0.1 represent the standard deviation.

Because the standard deviation is only 0.1, the distance between the mean (16) the the lower limit (30) is 140 standard deviations while the disance between the mean (16) and the upper limit (70) is 540 standard deviations. There is such a small amount between the lower limit and the upper limit that the amount between these two values is effectively zero.

You can cancel out the two (x - 2) factors, giving you  1 + x/(x - 3) > 0  and then solve from there.

However, because 2 makes the denominator in the fraction that you cancelled out equal to zero, you cannot have 2 as an answer.

$$\sqrt(81/29) = \sqrt(81)/\sqrt(29) = 9/\sqrt(29) = 9*\sqrt(29)/(\sqrt(29)*\sqrt(29)) = 9\sqrt(29)/29$$

Use a "z-score" to find the number of standard deviations a particular score has.(above or below the mean):

z-score  =  [ score - average ] / standard deviation

For example: if an IQ test has an average of 100 and a standard deviation of 15, then 

-- if your score is 130, your z-score is [ 130 - 100 ] / 15  =  30/15  =  2 (your score is 2 standard deviation above the mean)

-- if your score is 85, your z-score is [ 85 - 100 ] / 15  =  -15/15  =  -1 (your score is 1 standard deviation below the mean)

-- if your score is 105, your z-score is [ 105 - 100 ] / 15  =  5/15  = 0.3333 (your score is 0.3333 standard deviations above the mean).

Since there is a total of 26 socks, the probability of selecting a black or brown sock is 10/26.

The probability of selecting a white sock is 16/26.

The probability of selecting a black or brown sock first and then, with replacement, selecting a white sock is: 10/26 x 16/26  =  160/676   =  40/169  =  0.237

Since there is a total of 26 socks, the probability of selecting a black or brown sock is 10/26.

The probability of selecting a white sock is 16/26.

The probability of selecting a black or brown sock first and then, with replacement, selecting a white sock is: 10/26 x 16/26  =  160/676   =  40/169  =  0.237