OUTLIER

Outlier data point more than 1.5 interquartile range IQR below Q1 or above Q3 also both 

Ex

-8, 2,  5, 6,  9, 12, 22

     Q1   Q2     Q3                                                                                             1. Put in order

                                                                                                                         2. Q1=2

To find outlies:                                                                                                   Q3=12

      1 Q1-1.5(IQR)                                                                                            3. IQR ~ subtract Q3-Q1

         2-1.5(10)

         2-15= -13

      2 Q3+1.5(IQR)

         12+1.5(10)

          12+15=27

outlier

    no number less then -13            NO OUTLIER          no number greater then 27

PROBLEM:

111, 121, 159, 171, 179, 197, 325

         Q1           Q2            Q3

Subtract 121 from 197; 197-121=?

Then; 121-1.5(***)=?

Next; 197+1.5(***)+?

Once you have those numbers find the number that is less than Q1(then) or/and greater than Q3(next)

The mean of the data is 180.4

The standard deviation of the data is 70.8

An outlier is defined to be a value that is at least 1.5 standard deviations either above or below the mean.

1.5 x 70.8  =  106.2

Subtracting 106.2 from the mean gives 180.4 - 106.2  =  73.8. Since there is no value smaller than 73.8, there is no outlier below the mean.

Adding 106.2 to the mean gives 180.4 + 106.2  =  286.2.  Since 325 is greater than 286.2, 325 is an outlier.

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