1+x(x-2)/(x-3)(x-2)>0
why cant i just reduce the (x-2) and write 1+x/x-3>0 ?
why do i have to open the brackets?
You can also write it like this,In expanded for
(x^3-4 x^2+5 x-3)/(x-3)>0
In expanded form, like this:
x^3/(x-3)-(4 x^2)/(x-3)+(4 x)/(x-3)+1>0, therefore,
x>3
thank you but thats not what i asked
You can cancel out the two (x - 2) factors, giving you 1 + x/(x - 3) > 0 and then solve from there.
However, because 2 makes the denominator in the fraction that you cancelled out equal to zero, you cannot have 2 as an answer.
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