3.
Once we commonize the denominator, we achieve:
\(\frac{1}{\tan{x}}+\frac{1}{\cot{x}}=\frac{\tan{x}+\cot{x}}{\tan{x}\cdot\cot{x}}\)
Since, the problem gives us the numerical value:
\(\tan{x}+\cot{x}=\frac{144}{25}\),
we just need to solve for:
\(\tan{x}\cdot\cot{x}\).
Since \(\tan{x}\) and \( \cot{x}\) are recipricals, \(\tan{x}\) is opposite over adjacent and \( \cot{x}\) is adjacent over opposite, their product is equal to 1.
So our final expression becomes:
\(\frac{\frac{144}{25}}{1}\) , you can simplify.
I hope this helped,
Gavin