what is the larger root of the equation x^2-10x+21=0

Hey GM!

We can factor this quadratic:

\(x^2-10x+21=(x-7)(x-3)=0\)

I'm not going to explain how to factor the quadratic, but you can learn here:

https://www.mathsisfun.com/algebra/factoring-quadratics.html

We then get x = 7 and x = 3. 

7 is the larger root, 

I hope this helped,

Gavin

First, we take to move 21 to the other side. 

x^2-10x=-21

x=3, one root

But, \(\boxed{x=7}\) is also another root, which is larger than x=3.