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# what is the larger root of the equation x^2-10x+21=0

-5
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6
+-18

What is the larger root of the equation x^2-10x+21=0

What does the "larger root" mean?

May 19, 2018
edited by GAMEMASTERX40  May 19, 2018

#1
+988
+4

Hey GM!

\(x^2-10x+21=(x-7)(x-3)=0\)

I'm not going to explain how to factor the quadratic, but you can learn here:

We then get x = 7 and x = 3.

7 is the larger root,

I hope this helped,

Gavin

May 19, 2018
#2
+4299
+3

First, we take to move 21 to the other side.

x^2-10x=-21

x=3, one root

But, \(\boxed{x=7}\) is also another root, which is larger than x=3.

May 19, 2018
#3
+988
+3

Hey tertre, I don't understand how you got 3 just from moving 21 to the other side.

I'm pretty sure that's not how you solve a quadratic.

Are you just guess and checking?

GYanggg  May 19, 2018
#4
+4299
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Yes, I just guess and check!

tertre  May 19, 2018
#5
+988
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I that case, I guess that works too!

Nice job!

GYanggg  May 19, 2018
#6
+4299
+3

Thank you, Gavin!

tertre  May 20, 2018