hectictar

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Usernamehectictar
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 #3
avatar+9479 
+7

http://web2.0calc.com/questions/pie_16862

Check it out Davis :)

 

(Apparently that dude made an account but at the time of posting was a guest)

Mar 3, 2017
 #2
avatar+9479 
+2

I honestly forgot how to to this so I had to refresh my memory with this website.

http://www.purplemath.com/modules/fromzero.htm

I'm sure it can explain how to do these better than I can. :)

1.

y = a[x - (1+√2)][x - (1 - √2)]

y = a[x - 1 - √2][x- 1 + √2]

y = a(x2 - x + √2(x) - x + 1 - √2 - √2(x) + √2 - 2)

y = a(x2 - 2x - 1)

Since the y-intercept is -4, x is 0 when y is -4. Use this information to find a.

-4 = a(02 - 2(0) - 1)

-4 = a(-1)

4 = a

So

y = 4(x2 - 2x - 1)

y = 4x2 - 8x - 4

Or you could say:

f(x) = 4x2 - 8x - 4

-----------------------------------------------------

2.

The zeros are at x = 2 and x = 4.

y = a(x-2)(x-4)

y = a(x2 - 6x + 8)

y is -2 when x is 3

-2 = a(32 - 6(3) + 8)

-2 = a(9 - 18 + 8)

-2 = a(-1)

2 = a

So

y = 2(x2 - 6x + 8)

y = 2x2 - 12x + 16

Or you could say:

f(x) = 2x2 - 12x + 16

Mar 3, 2017
 #1
avatar+9479 
+1
Mar 3, 2017