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Given \(\vec{v}=3\vec{i}+4\vec{j}\) and \(\vec w=-2\vec i+7\vec j\) , decompose \(\vec v\) into two vectors \(\vec v_1\) and \(\vec v_2\) , where \(\vec v_1\) is parallel to \(\vec w\) and \(\vec v_2\) is orthogonal to \(\vec w\) .

I need help understanding this...

I do know how to "get the answer" but I don't "get" the answer.

hectictar Apr 25, 2018

#1**+4 **

It's been awhile since I did this...so...here goes nothing

v = (3, 4) w = (-2, 7)

We want to project v onto w

proj_{w} v = [( v dot w) /( length of w)^2 ] * w = [ 22/ 53) * (-2, 7) = (-44/53, 154/53)

This is v1

To find v2 we have [ v - v1] = (3, 4) - (-44/53, 154/53) = (203/53, 58/33)

Here's a pic :

The "why" of this always gave me some trouble, too. If I can remember what my Calc teacher said, if we shine a beam onto v from the "top" of the diagram perpendicular to v2, it will "project" a perfect "shadow" of v onto v2. Likewise....if we shine a beam from the "right" of the diagram onto v such that the beam is perpedicular to v1, it will "project" a perfect "shadow" of v onto v1.

Sorry, hectictar.....that's about as good of an explanation as I can supply......!!!!

I think this is used in Physics to break up components of work (as well as some other applications, too...)

CPhill Apr 25, 2018