I think the answer is:
Figure 4.4.3 = g
Figure 4.4.5 = g'
Figure 4.4.2 = g''
Figure 4.4.4 = g'''
Because:
Look at figure 4.4.3.... the "peaks of the hills" are where the slope = 0
The peaks of the hills on this graph occur around x = 0 and x = 2.9
The slope = 0 around x = 0 and x = 2.9
The derivative = 0 around x = 0 and x = 2.9
The graph of the derivative crosses the x axis around x = 0 and x = 2.9
And figure 4.4.5 does just that! So figure 4.4.5 must be the derivative of figure 4.4.3.
Figure 4.4.5 has peaks around x = 0, x = 1.8, and x = 3.8
The derivative of this graph should cross the x-axis around x = 0, x = 1.8, and x = 3.8
Figure 4.4.2 does this, so figure 4.4.2 must be the derivative of figure 4.4.5.
Then just continue with that train of thought.. That's just how I did it! 
