hectictar

Wow !! That is exciting news!

Congratulations Omi and Asinus !!!

Thank you for all your help around here!  

18/18 = 1

Any number, except 0, divided by itself = 1

\((3x^{\frac13})\cdot(8x^2) \\~\\ =3\cdot x^{\frac13}\cdot8\cdot x^2 \\~\\ =3\cdot8\cdot x^2\cdot x^{\frac13} \\~\\ =24\cdot x^{2+\frac13} \\~\\ =24\cdot x^{\frac73}\)

And x^(7/3) is the same thing as the cube root of ( x⁷ ) ....

\(=24\sqrt[3]{x^7}\)

Does that answer the question ?  

Ah okay..thanks for the explanation!  

Here's a 7, 8, and 9...(...These ones seemed a little too easy  )

\( 7=4+4-\frac44 \\~\\ 8=4+4*\frac44 \\~\\ 9=4+4+\frac44\)

I am not very good at these.....but here's ones for 2 and 3 and 4:

2 = \(\frac{4*4}{4+4}\)

3 =  \(\sqrt{4}+\sqrt4-\frac44\)

4 = \(4! - 4*4 - 4\)

Also...what do you mean by concatenation?

I looked it up but I still don't really know what it is

*edit*

I accidentally put 5 fours for 2...thanks to geno for letting me know!! 

π * 3² * 7   =   π * 9 * 7   =   63π   ≈  197.920   (if this is volume...)   cubic units

1 + 1 + 1 + 1 + 1 + 1 = 6

First press the 2nd button in the top left, then press "atan"

Also, you can type in " atan(  ) ," " arctan(  ) ," or " tan^-1(  ) " into the bar.

Any number ( except for 0 ) divided by itself = 1

\(\frac{\frac{3}{11}}{\frac{3}{11}}=1\)

I think this is your question:

cos^-1(0.9455)   =   acos(0.9455)   ≈   19º