hugomimihu

I suppose 4000-10= 3990, since it's 5%, divide that by 20? I think but might not be right answer it's been a while since I've last done expected value 

I assume the question meant none of the rolls could have a sum of 6

Actually 8000 isn't divisible by 180 it gets 44.444(recursive) instead.

I remember seeing this operation on the AMC10 a few months ago, but I've forgotten what it means

Could you please refresh my memory for me to help you?

What's your question?

6 outcomes/ dice, so 6^3 = 216 total outcomes

There are 6 ways of getting a trio of rolls with same numbers, 111,222,...666

We also have the ones with 2 numbers the same. 112,113, etc.

Each of the repeating digit(there's 6) has 3 positions to put the other non-same number, front, center, last, and 5 numbers to choose from, so 6*5*3 = 90 ways.

We ALSO have the ones with 3 different rolls but equal to 6. Each of these has 3! = 6 ways of arrangements.

1+2+3

I honestly don't think there are any else.

SO that's 6.

Adding all the ways, 6+6+90 = 102

So I'm pretty sure the answer's 102/216 = 51/108 and you can simplify that

If you don't understand feel free to ask.

It says positive, but whether 0 is positive or negative depends on your country.

For example I live in the US so 0 is neither, but in france, for instance, it's both.

So this (in my opinion) kind of depends on the definition of zero.

Then of course, it depends on whether the Guest's question is asking for just letter arrangements or actual words.

The question has some ambiguity on that.

Of course I have not done the question for myself and this is an untested suggestion.

But then it says "do not contain both 3 and 4", which could mean that there must not be 3 and 4 together.

Then we'd have to count for the ones with only a 3 or only a 4.

Guest who asked the question, please clarify the ambiguity.

Thanks.

Disregard my earlier suggestion