+0  
 
+8
111
2
avatar+902 

Here is a question I did when learning algebra thorugh the AoPS Intro to Algebra TEXTBOOK

 

Don't worry, this is from the textbook I'm self-learning and I've solved it.

 

This is also from an AMC12 so it's not a violation of copyright since I'm citing it

 

It's good for a exponent refresher.

 

Latex isn't working so here's the photo.

 

 

This should be relatively easy for the moderators and probably some of the regular users too

 

I did it in 3 minutes, my parents in like 30 seconds LOL

 

laugh

off-topic
 May 14, 2020
edited by hugomimihu  May 14, 2020
edited by hugomimihu  May 14, 2020
 #1
avatar+111438 
+4

     5^(48/x)                             1

_________________ =        ____

5^(26/x) * 25^(17/x)               25^2

 

 

5^(48/x - 26/x)                     1

_____________ =          ______ 

    (5^2)^(17/x)                   25^2

 

 

5^( 22/x)                       1

_______   =             ________              

5^(34/x)                     (5^2)^2

 

 

   1                             1

_______   =          _____

5^(12/x)                   5^4

 

Which implies that    12/x = 4     ⇒   x  = 3

 

 

cool cool cool

 May 14, 2020
 #2
avatar+902 
0

THis is how I did it(or similar, this is from a few days ago, doing it now)

 

So we first convert all 25^whatevers into 5^somethings

 

so

 

5^-4 = 5^48/x OVER 5^26/x * 5*34/x = 5 ^(48-26-34)x = 5^-12x

 

so -12x = -4, x = 3

 

essentially the same as what you did

 

laugh

 

And also I'd nominate your answer for "Best Answer"

hugomimihu  May 14, 2020
edited by hugomimihu  May 14, 2020

16 Online Users

avatar