idontknowhowtodivide

Okay, for a second I forgot that negative numbers could be squared to get a positive number. This thread is useless now, sorry for making it...

Thanks heureka for the help!

Using the Euclidean thereom, we can find that the largest integer value for n is 234. This question has been posted on several other different platforms as well...

The answer is 199.

The only possible values are the first piece is 75, the second 25, and the third 0. That's not 3 pieces, can you piece recheck your question?

Two must be the middle digit here, because if it is the end digit, then it would be even, not odd. So we have 5 numbers to include, 121, 323, 525, 727, and 929. Adding these numbers gets a total value of 2625.

Let s be the length of the smaller square and r be the length of the larger square. Using this, we have the system of equations:

s^2+80=r^2

4s+24=4r

First, we can simplify the second equation to s+6=r, so we know that s=r-6. Plugging this in the first equation gets us

(r-6)^2+80=r^2 --> r^2-12r+116=r^2. Now we now that -12r+116=0. This gives us r=29/3 and s=11/3. Your answer is 44/3 cm.

The equation for a parabola is y=ax^2+bx+c. We are given two points, and the axis of symmetry (x=12) which will be plenty for us.

The axis of symmetry can be found with the equation -b/2a=12. Solving for b, we get -b=24a, so b=-24a. Now we can turn our equation into:

y=ax^2-24ax+c. We can plug in the two points to get the two equations

-4=-144a+c

0=585a+c

Solving the system of linear equations, a=4/729 and c=-260/81. Now we can solve for b=-96/729.

Finding the other root of the quadratic 4/729x^2-96/729x-260/81=0, we get the other x-intercept to be (39, 0) or 39.

First, you seperate the rhombus into 4 congruent right triangles by drawing the diagonals. In one of these triangles, you know the hypotenuse is 148/4=37 units, and one of the legs is 10 units. Applying the Pythagorean theroem, 10^2+x^2=37^2, where x is the missing leg. Now you can subtract 10^2 on both sides to get x^2=1269. Take the square root of both sides to get x=sqrt1269=3sqrt141, so the answer of the diagonal is 2sqrt1296 as this x is only half of the diagonal, so the answer is 6sqrt141. 

Sorry if this is not correct, but I think that there would be 11 terms. Anyone willing to check?