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# geometric series

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Suppose that a, b, and c are real numbers for which

\begin{align*} a^2b^2 &= 28, \\ b^2c^2 &= 21, \text{ and}\\ a^2c^2 &= 27, \end{align*}. If a < b < c, find 3b. Don't know where to start. Any help or hints will be appreciated.

May 28, 2022