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Suppose that a, b, and c are real numbers for which

 

\(\begin{align*} a^2b^2 &= 28, \\ b^2c^2 &= 21, \text{ and}\\ a^2c^2 &= 27, \end{align*}\). If a < b < c, find 3b. Don't know where to start. Any help or hints will be appreciated.

 May 28, 2022
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Okay, for a second I forgot that negative numbers could be squared to get a positive number. This thread is useless now, sorry for making it...

 May 28, 2022

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